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Inverse Boundary Value Problem of Determining Up to a Second Order Tensor Appear in the Lower Order Perturbation of a Polyharmonic Operator

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We consider the following perturbed polyharmonic operator $$\mathcal {L}(x,D)$$L(x,D) of order 2m defined in a bounded domain $$\Omega \subset \mathbb {R}^n, n\ge 3$$Ω⊂Rn,n≥3 with smooth boundary, as $$ \mathcal {L}(x,D)… Click to show full abstract

We consider the following perturbed polyharmonic operator $$\mathcal {L}(x,D)$$L(x,D) of order 2m defined in a bounded domain $$\Omega \subset \mathbb {R}^n, n\ge 3$$Ω⊂Rn,n≥3 with smooth boundary, as $$ \mathcal {L}(x,D) \equiv (-\Delta )^m + \sum _{j,k=1}^{n}A_{jk} D_{j}D_{k} + \sum _{j=1}^{n}B_{j} D_{j} + q(x),$$L(x,D)≡(-Δ)m+∑j,k=1nAjkDjDk+∑j=1nBjDj+q(x), where A is a symmetric 2-tensor field, B and q are vector field and scalar potential respectively. We show that the coefficients $$A=[A_{jk}]$$A=[Ajk], $$B=(B_j)$$B=(Bj) and q can be recovered from the associated Dirichlet-to-Neumann data on the boundary. Note that this result shows an example of determining higher order (2nd order) symmetric tensor field in the class of inverse boundary value problem.

Keywords: order; inverse boundary; tensor; polyharmonic operator; value problem; boundary value

Journal Title: Journal of Fourier Analysis and Applications
Year Published: 2019

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