The layered magnetic topological insulator $\mathrm{MnB}{\mathrm{i}}_{2}\mathrm{T}{\mathrm{e}}_{4}$ is a promising platform to realize the quantum anomalous Hall effect because its layers possess intrinsic ferromagnetism. However, it is not well understood why… Click to show full abstract
The layered magnetic topological insulator $\mathrm{MnB}{\mathrm{i}}_{2}\mathrm{T}{\mathrm{e}}_{4}$ is a promising platform to realize the quantum anomalous Hall effect because its layers possess intrinsic ferromagnetism. However, it is not well understood why the high-spin ${d}^{5}$ magnetic ions $\mathrm{M}{\mathrm{n}}^{2+}$ forming the Mn-Te-Mn spin exchange paths prefer ferromagnetic (FM) coupling, contrary to the prediction of the Goodenough-Kanamori rule that a TM-$L$-TM spin exchange where TM and $L$ are a transition-metal magnetic cation and a main group ligand, respectively, is antiferromagnetic (AFM) even when the bond angle of the exchange path is 90\ifmmode^\circ\else\textdegree\fi{}. Using density functional theory calculations, we show that the presence of $\mathrm{B}{\mathrm{i}}^{3+}$ ions is essential for the FM coupling in $\mathrm{MnB}{\mathrm{i}}_{2}\mathrm{T}{\mathrm{e}}_{4}$. Then, using a tight-binding model Hamiltonian, we find that high-spin ${d}^{5}$ ions ($S=5/2$) in TM-$L$-TM spin exchange paths prefer FM coupling if the empty $p$ orbitals of a nonmagnetic cation $M$ (e.g., $\mathrm{B}{\mathrm{i}}^{3+}$ ion) hybridize strongly with those of the bridging ligand $L$ but AFM coupling otherwise.
               
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