Let 0 < mI ≤ A ≤ m′I ≤M′I ≤ B ≤MI and p ≥ 1. Then for every positive unital linear map Φ, Φ(A∇tB) ≤ ( K(h,2) 4 1… Click to show full abstract
Let 0 < mI ≤ A ≤ m′I ≤M′I ≤ B ≤MI and p ≥ 1. Then for every positive unital linear map Φ, Φ(A∇tB) ≤ ( K(h,2) 4 1 p −1(1+Q(t)(log M′ m′ ) 2) )Φ(A]tB) and Φ(A∇tB) ≤ ( K(h,2) 4 1 p −1(1+Q(t)(log M′ m′ ) 2) )(Φ(A)]tΦ(B)), where t ∈ [0, 1], h = m , K(h, 2) = (h+1)2 4h , Q(t) = t2 2 ( 1−t t ) 2t and Q(0) = Q(1) = 0. Moreover, we give an improvement for the operator version of Wielandt inequality.
               
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