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Published in 2020 at "Results in Mathematics"
DOI: 10.1007/s00025-020-01186-4
Abstract: It is well known that boundedness of a subadditive function need not imply its continuity. Here we prove that each subadditive function $$f:X\rightarrow {\mathbb {R}}$$ f : X → R bounded above on a shift–compact (non–Haar–null,…
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Keywords:
subadditive functions;
functions bounded;
bounded large;
large set ... See more keywords